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# Trying to solve a percent mixture?

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 8% vinegar, and the second brand contains 13% vinegar. The chef wants to make 280 milliliters of a dressing that is 11% vinegar. How much of each brand should she use?

1st brand:

2nd brand:

### 3 Answers

- PhilomelLv 71 month ago
use excel

107 0.08 8.56 173 0.13 22.49 0.1109108 0.08 8.64 172 0.13 22.36 0.1107109 0.08 8.72 171 0.13 22.23 0.1105111 0.08 8.88 169 0.13 21.97 0.1102112 0.08 8.96 168 0.13 21.84 0.1100112*.08=8.88, 168*.13=21.84

(8.88+21.84)/280=.1100=280mL(11%)

- TomVLv 71 month ago
The completed mixture must contain 280*0.11 = 30.8 ml of vinegar

Brand 1 contains 0.08 ml of vinegar per ml of dressing

Brand 2 contains 0.13 ml of vinegar per ml of dressing

The total amount of dressing must equal 280 ml.

Let x = number of ml of brand 1 and y = number of ml of brand 2.

Eq 1: x + y = 280 : total ml of dressing

Eq 2: 0.08x + 0.13y = 30.8 : total ml of vinegar in the dressing

Multiply Eq 1 by 0.08 and subtract from Eq 2:

0.08x - 0.08x + 0.13y - 0.08y = 30.8 - 0.08*280

0.05y = 8.4

y = 168 ml

Substitute the value of y into Eq 1, and solve for x:

x = 280 - 168 = 112 ml

ANS:

The chef uses 112 ml of Brand 1 and 168 ml of Brand 2

- KrishnamurthyLv 71 month ago
A chef is going to use a mixture of two brands of Italian dressing.

The first brand contains 8% vinegar, and the second brand contains 13% vinegar.

The chef wants to make 280 milliliters of a dressing that is 11% vinegar.

How much of each brand should she use?

Let V = vinegar

.08v +.13(280 - v) = .11(280)

.08v + 36.4 - .13v = 30.8

.05v = 5.6

v = 112

The chef needs 112 ml of the first dressing,

and 168 ml of the second to get his desired mixture.