Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Trying to solve a percent mixture?

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 8% vinegar, and the second brand contains 13% vinegar. The chef wants to make 280 milliliters of a dressing that is 11% vinegar. How much of each brand should she use?

1st brand:

2nd brand: 

3 Answers

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  • 1 month ago

    use excel

    107    0.08    8.56    173    0.13    22.49    0.1109108    0.08    8.64    172    0.13    22.36    0.1107109    0.08    8.72    171    0.13    22.23    0.1105111    0.08    8.88    169    0.13    21.97    0.1102112    0.08    8.96    168    0.13    21.84    0.1100112*.08=8.88,   168*.13=21.84

    (8.88+21.84)/280=.1100=280mL(11%)

  • TomV
    Lv 7
    1 month ago

    The completed mixture must contain 280*0.11 = 30.8 ml of vinegar

    Brand 1 contains 0.08 ml of vinegar per ml of dressing

    Brand 2 contains 0.13 ml of vinegar per ml of dressing

    The total amount of dressing must equal 280 ml.

    Let x = number of ml of brand 1 and y = number of ml of brand 2.

    Eq 1: x + y = 280 : total ml of dressing

    Eq 2: 0.08x + 0.13y = 30.8 : total ml of vinegar in the dressing

    Multiply Eq 1 by 0.08 and subtract from Eq 2:

    0.08x - 0.08x + 0.13y - 0.08y = 30.8 - 0.08*280

    0.05y = 8.4

    y = 168 ml

    Substitute the value of y into Eq 1, and solve for x:

    x = 280 - 168 = 112 ml

    ANS:

    The chef uses 112 ml of Brand 1 and 168 ml of Brand 2

  • 1 month ago

      A chef is going to use a mixture of two brands of Italian dressing. 

      The first brand contains 8% vinegar, and the second brand contains 13% vinegar. 

      The chef wants to make 280 milliliters of a dressing that is 11% vinegar. 

      How much of each brand should she use? 

      Let V = vinegar

     .08v +.13(280 - v) = .11(280)

     

     .08v + 36.4 - .13v = 30.8

     .05v = 5.6

      v = 112

     The chef needs 112 ml of the first dressing, 

     and 168 ml of the second to get his desired mixture.

     

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