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Trig ratios can someone help please?
Direct answer with explanation if possible :) thanks
- billrussell42Lv 73 months ago
sin A = opp/hyp = 5/13
cos A = adj/hyp = 12/13
tan A = opp/adj = 5/12
sin A = opp/hyp = 2/(2√5) = 1/√5 = √5/5cos A = adj/hyp = 4/(2√5) = 2/√5 = 2√5/5tan A = opp/adj = 2/4 = 1/2
- lenpol7Lv 73 months ago
SinA = BC/AB = 5/13
CosA = AC/AB = 12/13
TanA = BC/AC = 5/12
I shall leave you to do 9,10, and 11, otherwise you will not learn about Trig. Ratios.