How many grams of lead oxide will be produced by the decomposition of 267.2g of lead carbonat?

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  • 1 month ago

    First of all it is 'Lead Carbonate' ; note the 'e' on the end of 'carbonate'. 

    For the thermal decomposition of lead carbonate , write up the BALANCED reaction equation. 

    PbCO3 =ht=> PbO + CO2

    The molar ratios are 1::1:1 

    Next calculate the Mr of PbCO3 & PbO 

    PbCO3

    Pb x 1 = 207 x 1 = 207

    C x 1 = 12 x 1 = 12 

    Ox 3 = 16 x 3 = 48 

    207 + 12 + 48 = 267 

    PbO 

    Pb x 1 = 207 x 1 = 207

    O x 1 = 16 x 1 = 16

    207 + 16 = 223 

    Using the Equation 

    moles = mass(g) / Mr 

    mol(PbCO3) = 267.2/267 = 1.00075 moles (Equivalent to one molar ratio)

    mol(PbO) = 1.00075 moles( Also equivalent to '1' molar ratio)

    Hence 

    1.00075 = mass(g) / 223 

    mass(PbO) = 1.00075 x 223 = 223.167 g 

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