What is the change in momentum of a 45,000 kg airplane that crashes to the ground with a velocity of 120 m/ s?

Question

A. 375 kg m/s

B. 421

C. 6,000,000 kg m/s

D. 5.400,000 kg m/s

Answer 1

change in momentum  ΔM = m*ΔV

ΔV = (Vf-Vi) = (0-120) Δ M = ΔV*m = (0-120)*45,000 = -5,400,000 kg*m/sec

Answer 2

D. 5.400,000 kg m/s

the product of mass and change in velocity