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# What is the change in momentum of a 45,000 kg airplane that crashes to the ground with a velocity of 120 m/ s?

A. 375 kg m/s

B. 421

C. 6,000,000 kg m/s

D. 5.400,000 kg m/s

### 2 Answers

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- oubaasLv 71 month ago
change in momentum ΔM = m*ΔV

ΔV = (Vf-Vi) = (0-120) Δ M = ΔV*m = (0-120)*45,000 = -5,400,000 kg*m/sec

- Anonymous1 month ago
D. 5.400,000 kg m/s

the product of mass and change in velocity

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