Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

What is the change in momentum of a 45,000 kg airplane that crashes to the ground with a velocity of 120 m/ s?

A. 375 kg m/s

B. 421

C. 6,000,000 kg m/s

D. 5.400,000 kg m/s

2 Answers

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  • oubaas
    Lv 7
    1 month ago

    change in momentum  ΔM = m*ΔV

    ΔV = (Vf-Vi) = (0-120) Δ M = ΔV*m = (0-120)*45,000 = -5,400,000 kg*m/sec

  • Anonymous
    1 month ago

    D. 5.400,000 kg m/s

    the product of mass and change in velocity

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