Evaluate the indicated derivative at the point (1,2) and write the equation for the tangent line in slope-intercept form?
- VamanLv 71 month ago
Take the derivative.
dy/dx= -y^2/x^2, at x=1, y=2, the slope=-4
The equation is
y= -4x +c
This is the solution.
- az_lenderLv 71 month ago
You have not "indicated" any particular derivative, but I'll assume what's wanted is dy/dx.
1/y + 1/x = 2 =>
1/y = 2 - 1/x = (2x - 1)/x =>
y = x/(2x - 1) =>
dy/dx = [(2x - 1)*1 - (x)(2)] / (2x-1)^2
= -1/(2x - 1)^2
The point (1,2) is not on the given curve, so the meaning of the question is rather mysterious. Maybe they want a tangent from (1,2) TO the curve? But no, that doesn't work either, as any line through (1,2) will cross the given curve.
Either your teacher is a moron or you have miscopied the question.