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# Physics Help?

The area of the plates in a 5440 pF parallel plate capacitor is 6.4 x 10e-3 m2. Find the plate separation?

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- NCSLv 71 month ago
Another capacitance formula: C = Aε / d

and if only air is between the plates, ε = ε₀ = 8.85e-12 C²/N·m²

5440e-12 F = 6.4e-3m² * 8.85e-12 C²/N·m² / d

solves to d = 1.0e-5 m, or 10 µm

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