Anonymous asked in Science & MathematicsChemistry · 2 months ago

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341 L of a gas at 10oC are under 309 kPa of pressure. If the pressure is changed to 611 kPa and the temperature is decreased to -1oC, what volume will the gas occupy? (4 marks)

1 Answer

  • 2 months ago
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    Use the combined gas law:

    P1V1/T1 = P2V2/T2

    Remembering that your temperatures must be in Kelvin. So,

    309 kPa (341 L)/ 283 K = 611 kPa (V2) / 272 K

    V2 = 166 L

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