What is the solubility of Ag2CrO4 in 0.10 M K2CrO4?
- ?Lv 72 months ago
Ag2CrO4(s) = 2 Ag+(aq) + CrO4 2- (aq) Ksp = 1.2 x 10-12
We have for a solution of potassium chromate 0.1M
if s moles of the salt dissolves we get
(2s)2*(s+0.1) = 1.2×10−12
since s is small compared with 0,1 you can write:
Ksp = 4s^2 *.1 =0.4s^2 = 1,2×10−12
=SQRT( 1.2×10−12 / 0.4)
= 1.73*10^-6 moles/ liter
- Roger the MoleLv 72 months ago
It depends on the Ksp of Ag2CrO4.