A sealed container of an ideal gas at 280 K and 2.22 atm expands isothermally to 1.38 times its original volume. What is its final pressure?
- az_lenderLv 71 month agoFavorite Answer
When T is constant, then pV is also constant.
p(final) = (2.22 atm)*(1/1.38) = around 1.6 atm but use a calculator.
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