Calculate the volume of 1.60 mol of liquid water at a temperature of 20 ∘C ?
A. Calculate the volume of 1.60 mol of liquid water at a temperature of 20 ∘C (at which its density is 998 kg/m3)
B. Calculate the volume occupied by 1.60 mol of steam at 200 ∘C. Assume the steam is at atmospheric pressure and can be treated as an ideal gas.Express your answer in cubic meters to two significant figures.
- hcbiochemLv 71 month agoFavorite Answer
A. 998 kg/m^3 = 0.998 g/mL
1.60 mol X 18.016 g/mol / 0.998 g/mL = 28.9 mL
B. PV = n RT
1 atm ( V) = 1.60 mol (0.08206 Latm/molK) (473 K)
V = 62.1 L = 0.0621 m^3