Calculate the volume of 1.60 mol of liquid water at a temperature of 20 ∘C ?

Question

A. Calculate the volume of 1.60 mol of liquid water at a temperature of 20 ∘C (at which its density is 998 kg/m3)

B. Calculate the volume occupied by 1.60 mol of steam at 200 ∘C. Assume the steam is at atmospheric pressure and can be treated as an ideal gas.Express your answer in cubic meters to two significant figures.

Answer 1

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A. 998 kg/m^3 = 0.998 g/mL

1.60 mol X 18.016 g/mol / 0.998 g/mL = 28.9 mL 

B. PV = n RT

1 atm ( V) = 1.60 mol (0.08206 Latm/molK) (473 K)

V = 62.1 L = 0.0621 m^3