Two 4.0 cm ×4.0 cm square aluminum electrodes, spaced 0.50 mm apart, are connected to a 400 V battery.?
A. What is the capacitance? Express your answer in picofarads.
B. What is the charge on the positive electrode? Express your answer in coulombs.
- nyphdinmdLv 72 months agoFavorite Answer
For a parallel plate capacitor, C is given by
C = e0*K*A/d where K >= 1 for this problem K =1 since we have an air gap
then C = 28.32 pF
Charge can be found using C = Q/V -->> Q = CV = 1.13x10^-8 Coul