Barry asked in Science & MathematicsPhysics · 2 months ago

Two 4.0 cm ×4.0 cm square aluminum electrodes, spaced 0.50 mm apart, are connected to a 400 V battery.?

A. What is the capacitance? Express your answer in picofarads.

B. What is the charge on the positive electrode? Express your answer in coulombs.

1 Answer

  • 2 months ago
    Favorite Answer

    For a parallel plate capacitor, C is given by

      C = e0*K*A/d  where K >= 1  for this problem K  =1 since we have an air gap

    then  C = 28.32 pF

    Charge can be found using C = Q/V -->> Q = CV = 1.13x10^-8 Coul

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