# Can someone please solve this, and explain it to me? Relevance
• For all triangles 'x' is the sum of the two opposite interior angles, one of which has been given ; viz. 104 o

To find the other we have a straight line with an supplementary angle of  142 o . Now the angle of any point on a straight line is 180 o . So if we subtract 180 - 142 = 38 o , which is the other opposite interior angle.

So 'x' is 38 + 104 = 142 o

• When 2 angles are formed along a straight line, they must add up to 180. Also, all 3 angles inside of a triangle must add up to 180. Start solving the upper left hand corner angle, using the straight line rule.

• The uppermost angle in the triangle forms a straight line when combined with the 142° angle, so it must be 38°.

Angles of a triangle sum to 180°. If one is 38° and another is 104°, the third angle must be 38°.

Then that angle and x make another straight line.

• the sum of complimentary angles is 10 deg.

The sum of 3 interior angles of a triangle is 180 deg.

The top acute angle is 180-142=38 deg.

The lower acute angle is: 180-38-104=38 degrees.

The outer obtuse angle is: 180-38=142 deg.

• 1st solve the angle which is linier  to angle 142°. Let's call it angle y.

y° = 180 - 142 = 38°

next solving the other angle that is linier to angle x

z° = 180 - 104 - 38 = 38°

lastly, solving for x

since angle x and angle z are supplementary, we can solve for x by subtracting 180°.

x = 180 - 38 = 142°  Answer//

• x=104*+(180*-142*)=142*

• x = 104° + (180° - 142°) = 142°

• See below for work and solution. • We know:

Sum of the internal angles of a triangle is 180°

Supplementary angles sum to 180°

Putting those two together:

104° + (180-142)° + (180-x)° = 180°

(104 + 38 + 180) - x = 180

x = 104+38

x = 142°

• 180 -142 =  38

38 + 104 = 142

142 + x =180

x= 142