Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Based on Figure, determine the stretch in each spring for equilibrium of 2 kgblock. ?

The springs are shown in the equilibrium position. Given Fspring= ks 

(where s : stretch in the spring).

Attachment image

1 Answer

Relevance
  • NCS
    Lv 7
    2 months ago
    Favorite Answer

    Length of AC: Lac = √(3²+3²) m = √18 m

    Length of AB: Lab = √(3²+4²) m = 5 m

    For horizontal equilibrium at A,

    Tac*3/√18 = Tab*4/5 →→ Tac = 1.1314*Tab

    where Tac is the tension in spring AC

    For vertical equilibrium at A,

    Tac*3/√18 + Tab*3/5 = Tad

    and of course Tad = 2kg * 9.8m/s² = 19.6 N

    Substituting for Tac gives

    1.1314*Tab*3/√18 + Tab*0.6 = 19.6 N →→ Tab = 14 N

    and so Tac = 1.1314*14N = 16 N

    stretches:

    AC: 16N / 20N/m = 0.8 m

    AB: 14N / 30N/m = 0.5 m

    AD: 19.6N / 40N/m = 0.5 m

    all answers to one significant digit

    Hope this helps!

Still have questions? Get your answers by asking now.