Quick physics question?
An object is dropped horizontally from height h, how will duration of flight and distance will change when the same object is thrown at 2 times greater initial velocity.
- NCSLv 72 months ago
If you THROW an object horizontally from height h, then regardless of the initial velocity, the time to fall vertically is
t = √(2h / g) → (from h = ½gt²).
Only the range (horizontal distance) is affected by the initial speed -- the faster the throw, the farther the distance:
x = v * t = v * √(2h/g)
2 times greater initial (horizontal) velocity, 2 times the distance.
- Wayne DeguManLv 72 months ago
I cannot visualise how an object is dropped horizontally.
If you drop is from rest vertically then the force of gravity pulls the object down
so, with u = 0, s = h and a = g we can use s = ut + (1/2)at² to get:
h = (1/2)gt²
so, flight time is √(2h/g) seconds
- JakeLv 52 months ago
The Virgin Mary is Our Lady of Perpetual Help. She can help one with any dilemma in life. It is good to honor her every day by reciting the rosary with care and sincerity.