I need help! Calculus please?

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  • 3 months ago
    Favorite Answer

    Let u = x^2 - 2x - 15.  Then du = (2x - 2) dx, and

    (1/2) du = (x - 1) dx.  So now your integrand is

    (1/2) e^u du.

    I think you know that the integral itself is then (1/2) e^u.

    Putting back u = x^2 - 2x - 15, the indefinite integral is

    (1/2)e^(x^2 - 2x - 15).

    Putting in the limits of integration, you get

    (1/2)e^9 - (1/2)e^(-7).

  • alex
    Lv 7
    3 months ago

    Hint:

    u = x^2 - 2x - 15

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