What is the concentration (in Molarity) of an aqueous sodium chloride solution having on osmotic pressure of 22 atm at 18°C?

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  • Dr W
    Lv 7
    2 months ago

     use this equation

    .. P osmotic = i * M * R * T

    solving for M

    .. M = P osmotic / (i * R * T)

    .. ..  = 22 atm / (2 * 0.08206 Latm/molK * 291.15K) = 0.46M

  • 2 months ago

    (22 atm) / (18 + 273) K / (0.082057366 L atm/K mol) = 0.9213 mol/L ions

    NaCl ⇌ Na{+} + Cl{-}  [two ions]

    Supposing complete dissociation:

    (0.9213 mol/L ions) x (1 mol NaCl / 2 mol ions) = 0.46 mol/L NaCl

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