1. How many grams of Gallium Chloride are needed to prepare 470 mL of a 0.568 M solution ?

1 Answer

  • 2 months ago


    176.08 g/mol

    M = mol/L

    (0.568 mol)(176.08g/mol)= 100.01g

    100.01g/1000ml = 0.568 M

    so, 470ml (100.01g/1000ml) = 47.00g

    you need to add 47g of Gallium Chloride to 470 ml to get a 0.568 M solution

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