Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

If something has a mass of 1.899 x 10 (to the power of 27) and a density of 1.24 x 10 (to the power of 3) kg m (minus3), what is the volume? Volume is given by mass divided into density

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1.899e27 (kg?)

1.24e3 kg/m³

simple arithmetic

watch how the units cancel

1.899e27 kg / 1240 kg/m³ = 1.53e24 m³

or 1.53e15 km³

which is about the volume of Jupiter.

• // You omitted the units for mass, so I'm going to assume it's kg

mass = density x volume

mass       1.899 x 10²⁷ kg

volume = ---------- = ------------------------

density     1.24 x 10³ kg m⁻³

volume = 1.53 x 10²⁴ m³   .........................ANS

• There's a mistake in your wording. The formula for volume is mass divided *by* density (not *into* density).

Volume = density / mass <-- mass divided *into* density (WRONG!)

Volume = mass / density <-- mass divided *by* density (CORRECT)

You also didn't provide any units for your mass to know if there is a unit conversion.

Assuming your mass is in *kilograms*, you just divide the two numbers and that gives you the volume in cubic meters (m^3).

1.889 x 10^27 (kg) / (1.24 x 10^3) (kg/m^3)

= (1.889 / 1.24) * (10^27 / 10^3) (m^3)

≈ 1.52 * 10^24 m^3