A solution is prepared by dissolving 75.0 grams of sucrose (C12H22O11) in 200 grams water. What is the mass percent of sucrose this solution?

Answer 1

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Answer 2

mass % of sucrose = (mass of sucrose / Total mass) x 100 

= [(75.0 g)/(75.0 g + 200 g)] x 100 

= 27.27 %