How do you find the sides AX and CX?

Question

Answer 1

Hint:

Similar triangles

Answer 2

The two triangles are similar with vertices lining up as ABX ~ DCX so you make an extended proportion:

AB/DC = BX/CX = AX / DX then fill in the knowns

32/20 = 40/CX = AX/24

Then use the first ratio to make two equations, one with the second and one with the third, cross multiply and solve.

One would be 32/20 = 40/CX

32 CX = 40 • 20 = 800

CX = 800 ÷ 32