Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

How do you find the sides AX and CX?

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  • alex
    Lv 7
    2 months ago

    Hint:

    Similar triangles

  • 2 months ago

    The two triangles are similar with vertices lining up as ABX ~ DCX so you make an extended proportion:

    AB/DC = BX/CX = AX / DX then fill in the knowns

    32/20 = 40/CX = AX/24

    Then use the first ratio to make two equations, one with the second and one with the third, cross multiply and solve.

    One would be 32/20 = 40/CX

    32 CX = 40 • 20 = 800

    CX = 800 ÷ 32

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