Answer the following?

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  • Anonymous
    2 months ago

    This is not a question about Chemistry.  It needs moving to Mathematics.

  • Ash
    Lv 7
    2 months ago

    1+cot²θ = csc²θ

    cot²θ = csc²θ - 1

    tan²θ = 1/(csc²θ - 1)

    tanθ = - √[1/(csc²θ - 1)]     .... negative root is selected as θ belongs to QII

    tanθ = - √[1/((9/4)² - 1)]

    tanθ = - √[1/(81/16) - 1)]

    tanθ = - √[1/(65/16)]

    tanθ = - √(16/65)

    tanθ = - 4/√65

    cosθ = (cosθ/sinθ)*sinθ

    cosθ = (1/tanθ)(1/cscθ)

    cosθ = -((√65)/4)(4/9)

    cosθ = -(√65)/9

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