A 2.80-g lead bullet at 34.0°C is fired at a speed of 210 m/s into a large block of ice at 0°C, in which it becomes embedded. ?

Question

A 2.80-g lead bullet at 34.0°C is fired at a speed of 210 m/s into a large block of ice at 0°C, in which it becomes embedded. What quantity of ice melts?

Answer 1

KE + heat lost by lead = heat gained by ice

so it depends on what you take as the specific heat of lead

½mv² + mcΔT = M*L

where m = 0.00280 kg

and c = 160 J/kg·ºC (assumed -- check your reference tables)

ΔT = 34.0ºC

M = mass of ice that melts

L = 3.34e5 J/kg

I get M = 2.30e-4 kg = 0.230 g

If you find this helpful, please select Favorite Answer!