Answer to this question?

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8 Answers

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  • 2 months ago

    A = lw

    10 = x(x + 3)

    10 = x^2 + 3x

    x^2 + 3x - 10 = 0

    (x + 5)(x - 2) = 0

    x + 5 = 0, x - 2 = 0

    x = - 5, x = 2

    prefered x = 2 Answer//

    disregard x = - 5 since it's a negative number/

    solving its dimension

    L = 2

    w =  x + 3 = 2 + 3 = 5

     

  • 2 months ago

    (x+3)x=10

    =>

    x^2+3x=10

    =>

    x^2+3x-10=0

    =>

    x^2-2x+5x-10=0

    =>

    x(x-2)+5(x-2)=0

    =>

    (x-2)(x+5)=0

    =>

    x=2 or x=-5 (rejected, for x must not negative)

    =>

    x=2 cm is the answer.

  • 2 months ago

    The answer is 2 because if you think of all the multiplication facts that have a product of 10, you mostly can find out the answer quickly, for example, the first one that mostly comes to your mind is 5 x 2, but if you do 5 + 3 = 8 x 2, it's 16, that doesn't work. Or, flip it and do 2 x 5, 2 + 3 = 5 x 2 = 10

    So the answer is 2

  • 2 months ago

    A = (x + 3)(x) = 10 cm^2

    x^2 + 3x - 10 = (x + 5)(x - 2)

    x = 2

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  • 2 months ago

    A(x) = x(x + 3) = 10

    A(x) = x^2 + 3x = 10

    x^2 + 3x - 10 = 0

    (x + 5)(x - 2) = 0

    x = 2 is the only positive answer.  We must throw out -5, since lengths cannot be negative.

  • Ian H
    Lv 7
    2 months ago

    x*(x + 3) = 10

    By inspection x = 2 because 2* 5 = 10

    Not necessary to form and solve the quadratic

  • 2 months ago

    x²+3x=10

    x=2.    

  • 2 months ago

    area = height x width

    A = 10 = (x+3)(x)

    x² + 3x – 10 = 0

    (x + 5)(x – 2) = 0

    x = 2 (ignoring negative answer)

    rectangle is 2 x 5

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