The diameter of a cylindrical construction pipe is 6ft. If the pipe is 27ft long, what is its volume?

Answer 1

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Answer 2

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Answer 3

If it is a cylinder with an ID of 6 ft.

V= 2 pi R^2 L=6.28*3^2*27=1,526.814 cu ft.=1421.4 Gal

Answer 4

You failed to define the wall thickness of the pipe or if the 6 ft diameter is inside or outside diameter. Pipes of a nominal 6 ft size can be either

Answer 5

Volume = cross-sectional Area times Length

V = (𝞹r²) * L

V = 𝞹(3²) * 27 ft³ = 763.4ft³

or since 1 gallon = 231in³, then 5711 gallons

Answer 6

Somewhere between quite a bit and  sh*t ton.

Actually 3 x 3 x pi x 27

763.4 cubic feet