# How to solve this exercise in order to find x?

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• 4 hours ago

Extend O₁C  to D so that it intersects BO₂ in D.

Angle AO₁C = Angle O₂DO₁ = 52 degree ............... Alternate angles

Angle O₁CD = Angle O₁CO₂ + Angle O₂CD being linear pair

=> 180 degree  =  70 degree + Angle O₂CD

=> Angle O₂CD =  180 - 70  =  110 degree.

Now consider Triangle CO₂D :

Som of all the interior angles =  180 degree

=>  110° + 52° + x  =  180°

=> x = 70 - 52 = 18° ................................. Answer

• 16 hours ago

18°. Extend the exterior sides of the 70° angle until they meet the parallel lines. Solve for x.

• 24 hours ago

x + 52° = 70°

x = 18°

• 1 day ago

x = 18 degrees.

This is found by extending the line above the angle x to the line A.  This forms a triangle.  One of the angles is given as 52 degrees.  One of the angles is supplementary to 70 degrees; therefore it is 110 degrees.  The other angle is 18 degrees and is an alternate interior angle congruent to x.

• 1 day ago

Extend line O1 to line BO2.

Now you can easily determine 2 of the angles in the triangle, and x = 180 - sum of those 2.

• 1 day ago

are those two lines parallel? you don't say, but without that, this cannot be solved.

If they are, then

x = 180–110–52 = 18º

in more detail, draw line O₁DE, then CE

angle DEC = 90–52 = 38º

angle O₂DE = 180–70 = 110

angle O₂ED = 90–38 = 52

angle x = 180–110–52 = 18º