How to solve this exercise in order to find x?
- Pramod KumarLv 74 hours ago
Extend O₁C to D so that it intersects BO₂ in D.
Angle AO₁C = Angle O₂DO₁ = 52 degree ............... Alternate angles
Angle O₁CD = Angle O₁CO₂ + Angle O₂CD being linear pair
=> 180 degree = 70 degree + Angle O₂CD
=> Angle O₂CD = 180 - 70 = 110 degree.
Now consider Triangle CO₂D :
Som of all the interior angles = 180 degree
=> 110° + 52° + x = 180°
=> x = 70 - 52 = 18° ................................. Answer
- 16 hours ago
18°. Extend the exterior sides of the 70° angle until they meet the parallel lines. Solve for x.
- KrishnamurthyLv 724 hours ago
x + 52° = 70°
x = 18°
- stanschimLv 71 day ago
x = 18 degrees.
This is found by extending the line above the angle x to the line A. This forms a triangle. One of the angles is given as 52 degrees. One of the angles is supplementary to 70 degrees; therefore it is 110 degrees. The other angle is 18 degrees and is an alternate interior angle congruent to x.
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- nbsale (Freond)Lv 61 day ago
Extend line O1 to line BO2.
Now you can easily determine 2 of the angles in the triangle, and x = 180 - sum of those 2.
- billrussell42Lv 71 day ago
are those two lines parallel? you don't say, but without that, this cannot be solved.
If they are, then
x = 180–110–52 = 18º
in more detail, draw line O₁DE, then CE
angle DEC = 90–52 = 38º
angle O₂DE = 180–70 = 110
angle O₂ED = 90–38 = 52
angle x = 180–110–52 = 18º