How to solve this exercise in order to find x?

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6 Answers

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  • 4 hours ago

    Extend O₁C  to D so that it intersects BO₂ in D.

    Angle AO₁C = Angle O₂DO₁ = 52 degree ............... Alternate angles

    Angle O₁CD = Angle O₁CO₂ + Angle O₂CD being linear pair  

    => 180 degree  =  70 degree + Angle O₂CD

    => Angle O₂CD =  180 - 70  =  110 degree.

    Now consider Triangle CO₂D :

    Som of all the interior angles =  180 degree

    =>  110° + 52° + x  =  180°

    => x = 70 - 52 = 18° ................................. Answer

     

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  • 16 hours ago

    18°. Extend the exterior sides of the 70° angle until they meet the parallel lines. Solve for x.

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  • 24 hours ago

    x + 52° = 70°

    x = 18°

  • 1 day ago

    x = 18 degrees.

    This is found by extending the line above the angle x to the line A.  This forms a triangle.  One of the angles is given as 52 degrees.  One of the angles is supplementary to 70 degrees; therefore it is 110 degrees.  The other angle is 18 degrees and is an alternate interior angle congruent to x.

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  • 1 day ago

    Extend line O1 to line BO2.

    Now you can easily determine 2 of the angles in the triangle, and x = 180 - sum of those 2.

  • 1 day ago

    are those two lines parallel? you don't say, but without that, this cannot be solved.

    If they are, then

    x = 180–110–52 = 18º

    in more detail, draw line O₁DE, then CE

    angle DEC = 90–52 = 38º

    angle O₂DE = 180–70 = 110

    angle O₂ED = 90–38 = 52

    angle x = 180–110–52 = 18º

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