Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

Critical values of a function?

I am trying to solve for the critical values of the function f(x)=4x-tan(x)

f'(x) of this =4x-sec^2(x)

from here I have 1=(sec^2(x))/4x

from here I am unsure how to solve it

any help would be appreciated :)

2 Answers

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  • alex
    Lv 7
    2 months ago
    Favorite Answer

     f(x)=4x-tan(x)

    ---> f'(x)=4-sec^2(x) =0

    now you can do (not hard !)

  • Anonymous
    2 months ago

    I so wanted to answer this question.

    However, my answer is "Anonymous" as your post is Anonymous. There is no need for an Anonymous question in this category,

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