Critical values of a function?
I am trying to solve for the critical values of the function f(x)=4x-tan(x)
f'(x) of this =4x-sec^2(x)
from here I have 1=(sec^2(x))/4x
from here I am unsure how to solve it
any help would be appreciated :)
- alexLv 72 months agoFavorite Answer
---> f'(x)=4-sec^2(x) =0
now you can do (not hard !)
- Anonymous2 months ago
I so wanted to answer this question.
However, my answer is "Anonymous" as your post is Anonymous. There is no need for an Anonymous question in this category,