## Trending News

Promoted

Anonymous

# Critical values of a function?

I am trying to solve for the critical values of the function f(x)=4x-tan(x)

f'(x) of this =4x-sec^2(x)

from here I have 1=(sec^2(x))/4x

from here I am unsure how to solve it

any help would be appreciated :)

### 2 Answers

Relevance

- alexLv 72 months agoFavorite Answer
f(x)=4x-tan(x)

---> f'(x)=4-sec^2(x) =0

now you can do (not hard !)

- Anonymous2 months ago
I so wanted to answer this question.

However, my answer is "Anonymous" as your post is Anonymous. There is no need for an Anonymous question in this category,

Still have questions? Get your answers by asking now.