Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Help?? I don’t understand this question.?

Two forces are applied to a car in an effort to accelerate it, as shown below. The first force F1 = 308 N, is applied at an angle = 36° to the forward dashed line. The second force F2 = 508 N, is applied at an angle b? =9° To the forward dash line. 

What is the resultant of these two forces?

__ N at __ ° to the __ of the forward dash line

If the car has a mass of 2850 kg, what acceleration does it have? (Disregard friction) 

__ m/s^2 at __° to the __ of the forward dash line 

1 Answer

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  • NCS
    Lv 7
    2 months ago
    Favorite Answer

    You have to sum the forces. I'll demonstrate doing so by components. Parallel to the dashed line you have

    Fx = (308*cos36º + 508*cos-9º) N = 751 N

    assuming the two forces are on opposite sides of the dashed line. Perpendicular you have

    Fy = (308*sin36º + 508*sin-9º) N = 102 N

    toward the side with the 308 N force.

    resultant R = √(Fx² + Fy²) = 758 N

    and direction Θ = arctan(Fy/Fx) = 7.7º from the dashed line

    a = F / m = 0.266 m/s²

    in the same direction as the resultant.

    If you find this helpful, please select Favorite Answer!

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