Help?? I don’t understand this question.?
Two forces are applied to a car in an effort to accelerate it, as shown below. The first force F1 = 308 N, is applied at an angle = 36° to the forward dashed line. The second force F2 = 508 N, is applied at an angle b? =9° To the forward dash line.
What is the resultant of these two forces?
__ N at __ ° to the __ of the forward dash line
If the car has a mass of 2850 kg, what acceleration does it have? (Disregard friction)
__ m/s^2 at __° to the __ of the forward dash line
- NCSLv 72 months agoFavorite Answer
You have to sum the forces. I'll demonstrate doing so by components. Parallel to the dashed line you have
Fx = (308*cos36º + 508*cos-9º) N = 751 N
assuming the two forces are on opposite sides of the dashed line. Perpendicular you have
Fy = (308*sin36º + 508*sin-9º) N = 102 N
toward the side with the 308 N force.
resultant R = √(Fx² + Fy²) = 758 N
and direction Θ = arctan(Fy/Fx) = 7.7º from the dashed line
a = F / m = 0.266 m/s²
in the same direction as the resultant.
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