Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

# Help?? I don’t understand this question.?

Two forces are applied to a car in an effort to accelerate it, as shown below. The first force F1 = 308 N, is applied at an angle = 36° to the forward dashed line. The second force F2 = 508 N, is applied at an angle b? =9° To the forward dash line.

What is the resultant of these two forces?

__ N at __ ° to the __ of the forward dash line

If the car has a mass of 2850 kg, what acceleration does it have? (Disregard friction)

__ m/s^2 at __° to the __ of the forward dash line

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• NCS
Lv 7
2 months ago

You have to sum the forces. I'll demonstrate doing so by components. Parallel to the dashed line you have

Fx = (308*cos36º + 508*cos-9º) N = 751 N

assuming the two forces are on opposite sides of the dashed line. Perpendicular you have

Fy = (308*sin36º + 508*sin-9º) N = 102 N

toward the side with the 308 N force.

resultant R = √(Fx² + Fy²) = 758 N

and direction Θ = arctan(Fy/Fx) = 7.7º from the dashed line

a = F / m = 0.266 m/s²

in the same direction as the resultant.