? asked in Science & MathematicsPhysics · 2 months ago

Physics: Circular Motion?

A certain string just breaks when it is under 25 N of tension. A boy uses this string to whirl a 0.75-kg stone in a horizontal circle of radius 2.0 m. The boy continuously increases the speed of the stone. At approximately what speed with the string break?

Please help

1 Answer

  • 2 months ago
    Favorite Answer

    Centrifugal force

    F = mv²/r


    m - mass of stone

    v - speed

    r - radius of circle

    Find v such that F exceeds 25N required to break a string

    v = √(Fr/m)

    v = √(25*2/0.75) = 8.16 m/s

    Attachment image
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