pls help #3 ?

The force exerted on the small piston of a hydraulic lift is 1200 N. if the area of the small piston is 0.85 square meters and the area of the large piston is 1.26 square meters, what is the force exerted by the large piston? 

F2 = 1700.9 N

F2 = 1778.8 N

F2 = 1560.3 N

F2 = 1680.1 N

1 Answer

  • 4 months ago
    Favorite Answer

    (1200/.85)*1.26=1778.8N.            .

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