Can I get help writing a balanced equation for the neutralization of calcium hydroxide with nitric acid?

Question

to help understand the ? better: how many moles of calcium hydroxide are needed to completely neutralize 6 moles of nitric acid?

(Your answer should be a number and nothing else)

Answer 1

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Nitric Acid + Calcium hydroxide ➜ calcium nitrate + water

2HNO₃ + Ca(OH)₂ ➜ Ca(NO₃)₂ + 2H₂O

or

2 moles of HNO₃ + 1 mole of Ca(OH)₂ ➜ 1 mole of Ca(NO₃)₂ + 2 mole of H₂O

ratio of Ca(OH)₂ to HNO₃ is 1/2

1/2 = x/6

x = 3 moles

Answer 2

Ca(OH)2 + 2 HNO3 --> Ca(NO3)2 + 2 H2O

6 mol HNO3 X (1 mol Ca(OH)2 / 2 mol HNO3) = 3 mol Ca(OH)2