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# Kinetics Physics question help?

A child goes down a playground slide with an acceleration of 1.34 m/s^2

Find the coefficient of kinetic friction between the child and the slide if the slide is inclined at an angle of 35.0 ∘ below the horizontal.

### 2 Answers

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- Wayne DeguManLv 73 months agoFavorite Answer
Resolving down the plane and perpendicular we have:

(↙) mgsin35° - Fric = 1.34m....(using F = ma)

(↖) R = mgcos35°

Also, Friction = µ.R

i.e. Friction = µmgcos35°

so, mgsin35° - µmgcos35° = 1.34m

Hence, gsin35° - µgcos35° = 1.34

Then, µgcos35° = gsin35° - 1.34

so, µ = (gsin35° - 1.34)/gcos35°

Therefore, µ = 0.53

:)>

- NCSLv 73 months ago
acceleration down incline with friction

a = g*(sinΘ - µ*cosΘ)

1.34 m/s² = 9.81m/s² * (sin35.0º - µ*cos35.0º)

solves to µ = 0.533

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