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# what is the second derivative of this function f(x) = [x^2sin(x)cos(x)] / [sin(2x)]?

i tried taking the natural logarithm and when i was trying to find the second derivative it all became so long. does anyone know how to solve this and explain it to me?

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- stanschimLv 74 weeks agoFavorite Answer
f(x) = [(x^2)sin(x)cos(x)] / sin(2x)

f(x) = [(x^2)sin(x)cos(x)] / [2sin(x)cos(x)] Using trig identity

f(x) = (1/2)x^2

f'(x) = x

f''(x) = 1

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