what is the second derivative of this function f(x) = [x^2sin(x)cos(x)] / [sin(2x)]?
i tried taking the natural logarithm and when i was trying to find the second derivative it all became so long. does anyone know how to solve this and explain it to me?
- stanschimLv 74 weeks agoFavorite Answer
f(x) = [(x^2)sin(x)cos(x)] / sin(2x)
f(x) = [(x^2)sin(x)cos(x)] / [2sin(x)cos(x)] Using trig identity
f(x) = (1/2)x^2
f'(x) = x
f''(x) = 1