What is the initial velocity of a ball thrown straight up in the air, that reaches its highest point at 8.8 seconds?

1 Answer

Relevance
  • 1 month ago

    at the highest point the speed of the ball is momentarily zero as it changes direction and starts to fall.  So you can use

    v(t) = a*t + v0  and set t = 8.8 sec,  a = g = -9.8 m/s^2 and v(t) = 0 to solve for v0

    v0 = v(t) - a*t = 0 - (-9.8 m/s^2)*8.8s = 862.4 m/s

Still have questions? Get your answers by asking now.