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# What is the initial velocity of a ball thrown straight up in the air, that reaches its highest point at 8.8 seconds?

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- nyphdinmdLv 71 month ago
at the highest point the speed of the ball is momentarily zero as it changes direction and starts to fall. So you can use

v(t) = a*t + v0 and set t = 8.8 sec, a = g = -9.8 m/s^2 and v(t) = 0 to solve for v0

v0 = v(t) - a*t = 0 - (-9.8 m/s^2)*8.8s = 862.4 m/s

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