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# Physics help please?

A car speeds up from 50m/s to 100m/s in 3s. How far did the car travel during this acceleration

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- oubaasLv 71 month agoFavorite Answer
acceleration a = (Vf-Vi)/t = (100-50)/3 = 50/3 m/sec^2

computation of distance d :

d = (Vi+Vf)*t/2 = 150*3/2 = 225 m

d = (Vf^2-Vi^2)/2a = (10,000-2,500)*3/100 = 75*3 = 225 m

d = Vi*t+a/2*t^2 = 50*3+50/6*3^2 = 150+50*1.5 = 150+75 = 225 m

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