Calculate mass of Copper(II) acetate monohydrate.... (from solution-detail inside)?
Calculate mass of Copper(II) acetate monohydrate needed to prepare 100.0 mL of 0.1250 M solution from solid Copper(II) acetate monohydrateI really confused on how to start it. I really tried but am beyond stuck. I also like to learn on how exactly to do this problem-so what topic should i search on youtube? thx
- hcbiochemLv 74 weeks agoFavorite Answer
Calculate the moles of Cu(II) acetate [Cu(C2H5O2)2*H2O] required:
0.1250 mol/L X 0.1000 L = 0.01250 mol Cu(C2H5O2)2*H2O
The molar mass of the compound is 199.65 g/mol (Are you OK with figuring that out?)
Mass Cu(C2H5O2)2*H2O = 0.01250 mol X 199.65 g/mol = 2.496 g