What is the temperature?
Question. The temperature of an object in degrees Fahrenheit after t minutes is represented by the equation T(t) = 68e-0.0174t + 72. To the nearest degree, what is the temperature of the object after one and a half hours?
How to solve this question?
What is the formula?
revised : T(t) = 68e^-0.0174t + 72
- PuzzlingLv 71 month ago
You have the formula, but let me correct your notation slightly:
T(t) = 68e^(-0.0174t) + 72
Also, the time (t) is given in *minutes*.
1.5 hours = 90 minutes
T(90) = 68e^(-0.0174*90) + 72
T(90) ≈ 86°F
Note: If you graph it, you'll see that the temperature starts at 140°F and is asymptotically approaching the ambient room temperature of 72°F. After 1½ hours (90 minutes), it has cooled down to about 86°F
Your revised equation is still technically incorrect. You need to include the t inside parentheses. The exponent takes precedence over the multiplication by t if you don't group the two together. Example: 2^(3t) is different than 2^3t = (2^3)t = 8tSource(s): https://www.google.com/search?q=68e%5E(-0.0174*90)... https://www.desmos.com/calculator/hguw7xjezv
- rotchmLv 71 month ago
t is in minutes. So at a time of one and a half hours, how many minutes is that?
Now, replace this value you just found by "t" and put it in the formula & compute.
What do you finally get?
Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.