Solving applications of Boyle's Law?

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  • 1 month ago

    volume of a sphere = (4/3) pi r^3

    r = 34 cm, so

    V = (4/3) (3.14159) (34)^3 = 1.646X10^6 cm^3 = 164.6 L

    Now, you must assume that the needed air is measured at 1 atm pressure, since no pressure was given in the problem. So,

    P1V1 = P2V2

    1 atm (3300 L) = P2 (164.6 L)

    P2 = 20 atm

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