Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

13.16 You want to prepare an aqueous solution of ethylene glycol, HOCH2CH2OH, in which the mole fraction of solute is 0.120.?

What mass of ethylene glycol, in grams, should you combine with 955 g of water?

Mass = ??? g

1 Answer

Relevance
  • 1 month ago

    1 - 0.120 =  0.880 (mole fraction of water)

    (955 g H2O) / (18.01532 g H2O/mol) / (0.880) = 60.239 mol total

    (60.239 mol total) - ((955 g H2O) / (18.01532 g H2O/mol)) = 7.22856 mol solute

    (7.22856 mol HOCH2CH2OH) x (62.0678 g HOCH2CH2OH/mol) = 448.66 g =

    449 g HOCH2CH2OH

Still have questions? Get your answers by asking now.