D asked in Science & MathematicsPhysics · 1 month ago

# Physics Acceleration?

The extinct mega bird Aepyornis maximus (shown above in relative scale) was running at an inital speed of 15.1 m/s and slowed to a final speed of 12.6 m/s. The time for the change in velocity is 2.2 s.

Compute the acceleration of Aepyornis maximus in m/s^2.

If the bird continued to slow down at the rate above, what will be it's final speed in m/s after 5.2 seconds?

Relevance
• 1 month ago

u = 15.1, v = 12.6 and t = 2.2

so, using v = u + at we have:

12.6 = 15.1 + 2.2a

so, a = (12.6 - 15.1)/2.2 => -1.14 ms⁻²

Then, we have u = 15.1, a = -1.14 and t = 5.2

Hence, v = 15.1 - 1.14(5.2) => 9.2 ms⁻¹

:)>

• NCS
Lv 7
1 month ago

a = Δv / Δt = (12.6 - 15.1)m/s / 2.2s = -1.14 m/s²

5.2 seconds after which velocity measurement?

From the initial velocity (most reasonable, IMO)

v = 15.1m/s - 5.2s*1.14m/s² = 9.19 m/s

But if they meant "after an ADDITIONAL 5.2 seconds, then

v = 12.6m/s - 5.2s*1.14m/s² = 6.69 m/s

Hope this helps!