The extinct mega bird Aepyornis maximus (shown above in relative scale) was running at an inital speed of 15.1 m/s and slowed to a final speed of 12.6 m/s. The time for the change in velocity is 2.2 s.
Compute the acceleration of Aepyornis maximus in m/s^2.
If the bird continued to slow down at the rate above, what will be it's final speed in m/s after 5.2 seconds?
- Wayne DeguManLv 71 month agoFavorite Answer
u = 15.1, v = 12.6 and t = 2.2
so, using v = u + at we have:
12.6 = 15.1 + 2.2a
so, a = (12.6 - 15.1)/2.2 => -1.14 ms⁻²
Then, we have u = 15.1, a = -1.14 and t = 5.2
Hence, v = 15.1 - 1.14(5.2) => 9.2 ms⁻¹
- NCSLv 71 month ago
a = Δv / Δt = (12.6 - 15.1)m/s / 2.2s = -1.14 m/s²
5.2 seconds after which velocity measurement?
From the initial velocity (most reasonable, IMO)
v = 15.1m/s - 5.2s*1.14m/s² = 9.19 m/s
But if they meant "after an ADDITIONAL 5.2 seconds, then
v = 12.6m/s - 5.2s*1.14m/s² = 6.69 m/s
Hope this helps!Source(s): Hey, was this working helpful? https://answers.yahoo.com/question/index?qid=20201...
- billrussell42Lv 71 month ago
shown above ??