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# Can someone help me with this equation?

I am confused

### 6 Answers

- lenpol7Lv 71 month ago
Write it down as factors.

The top (numerator) 's factors are 7 x 6 x y x z x z

The bottom (denomiantor)'s factors are 4 x 6 x y x y x y x z x z

There is one '6' top and bottom, so cancel down

There is one 'y' on the top , so cancel down with one 'y' on the bottom. This will leave two 'y' on the bottom.

There two 'z' on both the top and bottom so cancel down both 'z' .

Hence we are left with

7/(4y^2) the simplified answer.

- charlatanLv 71 month ago
42*(y^(1-3)*z^(2-2))/24

7*(y^(-2)*z^(0))/4

=7/4y^2

@JohnP you are not alone,you are already a member of the popular club.

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- Anonymous1 month ago
Gosh, I was never much good at maths at school 60 years ago, but I think I have managed to work it out in less than a minute. Just in case I have got it wrong, I will not show my answer.

- MichaelLv 71 month ago
reduce numbers in the normal fashion

42/24 = 7/4

exponents on the variables cancel by subtraction

since y is y¹ subtract 1 from the exponent of both numerator and denominator

y/y³ = y⁰/y² = 1/y²

cancel by subtracting 2 from the exponent of both numerator and denominator

z²/z² = z⁰ / z⁰ = 1/1 = 1

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All together

7

–––– <––––––––

4y²