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# Find the partial derivative of f(x,y,z)=x^2y+6z^3xy?

Find the partial derivative of f(x,y,z)=x^2y+6z^3xy

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- rotchmLv 71 month ago
Hint: Partial derivatives is like "normal derivatives".

For instance, if you want fx, then take y & z as constants, and differentiate the function (wrt x). Try it on your own now! What do you get?

Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.

- Engr. RonaldLv 71 month ago
f(x,y,z)=x^2y+6z^3xy

fx = 2xy + 6z^3y answer//

fy = x^2 + 6z^3x answer//

fz = 18z^2xy answer//

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