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# A 16- foot tree casts a shadow that is 8 feet long. What is the distance from the top of the tree to the end of the shadow? ?

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- PinkgreenLv 74 weeks ago
Let the tree top be A; the end of the shadow of it be B & the foot of the tree

be O. assume that the tree is straight, then

AB^2=OA^2+OB^2

=>

AB=sqr(16^2+8^2)

=>

AB=sqr(320)

=>

AB=8sqr(5)~17.9 ft.

- DavidLv 71 month ago
Using Pythagoras for a right angle triangle is 8 times the square root of 5 or about 17.89 feet rounded to two decimal places

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- llafferLv 71 month ago
If you sketch this out you get a right triangle with a height of 16 feet and abase of 8 feet.

You are looking for the hypotenuse of this triangle, so:

a² + b² = c²

16² + 8² = c²

256 + 64 = c²

320 = c²

c = √320

c = √(64 * 5)

c = 8√5 feet

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