A 16- foot tree casts a shadow that is 8 feet long. What is the distance from the top of the tree to the end of the shadow? ?

5 Answers

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  • 4 weeks ago

    Let the tree top be A; the end of the shadow of it be B & the foot of the tree

    be O. assume that the tree is straight, then

    AB^2=OA^2+OB^2

    =>

    AB=sqr(16^2+8^2)

    =>

    AB=sqr(320)

    =>

    AB=8sqr(5)~17.9 ft.

  • 1 month ago

    Ask Pythagoras. He developed a formula.

  • 1 month ago

    √(16² + 8²) = 17.89 ft

  • David
    Lv 7
    1 month ago

    Using Pythagoras for a right angle triangle is 8 times the square root of 5 or about 17.89 feet rounded to two decimal places

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  • 1 month ago

    If you sketch this out you get a right triangle with a height of 16 feet and abase of 8 feet.

    You are looking for the hypotenuse of this triangle, so:

    a² + b² = c²

    16² + 8² = c²

    256 + 64 = c²

    320 = c²

    c = √320

    c = √(64 * 5)

    c = 8√5 feet

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