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# help me with this physics question PLEASE?

The figure shows two vectors B and C, along with their magnitudes and directions. The vector D is given by D = B - C

A) What is the magnitude of vector D?

B) What angle does vector D make with the +x axis (give the angle between 0 degrees and 360 degrees)?

THANKS SO MUCH

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- NCSLv 71 month agoFavorite Answer
D = B - C = B + -C

Dx = -(6*sin53º + 4*cos32º) = -8.184

Dy = -(6*cos53º + 4*sin32º) = -5.731

magnitude |D| = √(Dx² + Dy²) ≈ 10

angle Θ = arctan(Dy/Dx) = 35º below -x axis = 215º

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