help me with this physics question PLEASE?
The figure shows two vectors B and C, along with their magnitudes and directions. The vector D is given by D = B - C
A) What is the magnitude of vector D?
B) What angle does vector D make with the +x axis (give the angle between 0 degrees and 360 degrees)?
THANKS SO MUCH
- NCSLv 71 month agoFavorite Answer
D = B - C = B + -C
Dx = -(6*sin53º + 4*cos32º) = -8.184
Dy = -(6*cos53º + 4*sin32º) = -5.731
magnitude |D| = √(Dx² + Dy²) ≈ 10
angle Θ = arctan(Dy/Dx) = 35º below -x axis = 215º
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