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# grams of sodium azide?

How many grams of sodium azide are needed to provide sufficient nitrogen gas to fill a 35.0 × 35.0 × 25.0 cm bag to a pressure of 1.11 atm at 21.0 °C?

### 1 Answer

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- BobbyLv 72 months ago
35.0 × 35.0 × 25 = 30625 cm^3 or 30.625 L

Using the universal gas equation we have

moles of N2 = 1.11 atm * 30.625 L / 0.0820 L⋅atm⋅K−1⋅mol−1 * 294 K

= 1.410 moles

2NaN3 = 2Na+ 3N2

moles of NaN3 needed for the given moles of N2 = 1.410 moles * 2 / 3

= 0.940 moles of NaN3 = 0.940 * 65.00 g / mol = 61.1 g of NaN3

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