how do i use the stoich/ice box to find the complete ionic equation for Na2CO3 + CaCl2 = 2NaCl + CaCO3? I only know how to do it normally.. ?
- hcbiochemLv 71 month ago
You don't need an ICE table or stoichiometry to figure out the complete ionic equation. The only think you need to figure out is whether any of these compounds are not soluble and so might form a precipitate. Of the things in the equation, the solubility rules indicate that 3 are soluble and one is not. So, CaCO3 is not soluble and will precipitate from the solution. So, the complete ionic equation is:
2 Na+(aq) + CO32-(aq) + Ca2+(aq) + 2 Cl-(aq) --> CaCO3(s) + 2 Na+(aq) + 2 Cl-(aq)
Unless there is more to the problem, something involving concentrations and changes in concentration, or amounts of CaCO3 formed, stoichiometry and ICE tables play no role.