# how do i make a multiplication table with # of rows/columns depending on the user's input?

so far i only have the user input codes done but im so lost. i tried to watch youtube videos but none of them is right for what i am doing.

so basically i have to ask how many rows they would like and the output should be a multiplication table up to that number. i have no idea how to do this. i got the rows and columns done already but idk how i should put the actual numbers.... idk if this makes sense.

Relevance
• 6 days ago

What language are you programming in?

You will be using nested for loops to create your table.

Basically, your pseudocode for the table would be:

for row = 0 to n:

for column = 0 to n:

if row=0:

if column=0: print "x"+tab

else: print column+tab

else:

if column=0: print row+tab

else: print row*column + tab

end for column

print newline

end for row

• EddieJ
Lv 7
6 days ago

int main () {

int integer = 0;

int even = 0;

int odd = 0;

const int SENTINEL = -999;

cout << "Enter an integer ending with -999: " << endl;

while (true) {

cin >> integer;

if (integer == SENTINEL) break;

if (integer % 2 == 0) even += integer;

else odd += integer;

}

cout << "The sum of your even integers is: " << even << endl;

cout << "The sum of your odd integers is: " << odd << endl;

}