# how do i make a multiplication table with # of rows/columns depending on the user's input?

so far i only have the user input codes done but im so lost. i tried to watch youtube videos but none of them is right for what i am doing.

so basically i have to ask how many rows they would like and the output should be a multiplication table up to that number. i have no idea how to do this. i got the rows and columns done already but idk how i should put the actual numbers.... idk if this makes sense. Relevance

What language are you programming in?

You will be using nested for loops to create your table.

Basically, your pseudocode for the table would be:

for row = 0 to n:

for column = 0 to n:

if row=0:

if column=0: print "x"+tab

else: print column+tab

else:

if column=0: print row+tab

else: print row*column + tab

end for column

print newline

end for row

• int main () {

int integer = 0;

int even = 0;

int odd = 0;

const int SENTINEL = -999;

cout << "Enter an integer ending with -999: " << endl;

while (true) {

cin >> integer;

if (integer == SENTINEL) break;

if (integer % 2 == 0) even += integer;

else odd += integer;

}

cout << "The sum of your even integers is: " << even << endl;

cout << "The sum of your odd integers is: " << odd << endl;

}