rank the following solutions from lowest to highest freezing point?
1.0 m fructose
0.7 m CaCl2
1.0 m NaCl
0.5 M Na3PO4
- Roger the MoleLv 74 weeks ago
0.7 m CaCl2 < 1.0 m NaCl < 0.5 M Na3PO4 < 1.0 m fructose
although the difference in freezing points among the three that are not fructose probably can't be detected within the given significant digits
- ChemTeamLv 74 weeks ago
You have to look at the total concentration of particles in solution. For that, you need to consider each substance's van 't Hoff factor.
What you do is multiply the given conc. by the van 't Hoff factor to give the total conc. of particles.
fructose (i = 1) will be 1.0 m
CaCl2 (i = 3) will be 2.1 m
NaCl (i = 2) and Na3PO4 (i = 4)
The solution with the highest concentration will have the largest fp depression, resulting in the lowest fp.
The solution with the lowest conc will have the smallest fp depression, resulting in the highest fp.