A 2000-kg elevator with broken cables in a test rig is falling at when it contacts a cushioning spring at the bottom of the shaft.?
The spring is intended to stop the elevator, compressing 2.00 m as it does so. During the motion a safety clamp applies a constant 17,000-N frictional force to the
elevator. What is the necessary force constant k for the spring?
- Andrew SmithLv 71 month ago
Without giving the height it has fallen there is no possible answer.
Ek = (mg-17000)*h
1/2 k x^2 = Ek -> 1/2 *k * 4 = (mg-17000)*h
-> k = (2000*9.8 - 17000)*h/2