A 2000-kg elevator with broken cables in a test rig is falling at when it contacts a cushioning spring at the bottom of the shaft.?

The spring is intended to stop the elevator, compressing 2.00 m as it does so. During the motion a safety clamp applies a constant 17,000-N frictional force to the

elevator. What is the necessary force constant k for the spring?

1 Answer

  • 1 month ago

    Without giving the height it has fallen there is no possible answer.

    Ek = (mg-17000)*h

    1/2 k x^2 = Ek -> 1/2 *k * 4 = (mg-17000)*h

    -> k = (2000*9.8 - 17000)*h/2

Still have questions? Get your answers by asking now.