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# What wavelength (in nm) is observed when an electron in a helium atom transitions from n=3 to n=2?

I really need help calculating energy loss please!!!

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- andrewLv 71 month agoFavorite Answer
Atomic number of helium, Z = 2

Rydberg constant, R = 1.097 × 10⁷ m⁻¹ = 1.097 × 10⁻² nm⁻¹

n₂ = 3 to n₁ = 2

Rydberg equation: 1/λ = RZ² [(1/n₁²) - (1/n₂²)]

Then, λ = 1 / {RZ² [(1/n₁²) - (1/n₂²)]}

Wavelength, λ

= 1 / {1.097 × 10⁻² × 2² × [(1/2²) - (1/3²)] nm

= 164.1 nm

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