If a 130.76g sample of Zinc reacts with excess hydrochloric acid, 2.01 moles of H2(g) are produced. Calculate the Molar Mass of Zinc.
- 戇戇居士Lv 71 month ago
Balanced equation for the reaction:
Zn + 2HCl → ZnCl₂ + H₂
Mole ratio Zn : H₂ = 1 : 1
Moles of Zn reacted = Moles of H₂ produced = 2.01 mol
Molar mass of Zn = (130.76 g) / (2.01 mol) = 65.1 g/mol
(to 3 sig. fig.)
- Anonymous1 month ago
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